If a,b,c are in A.P a,b,d are in G.P,Show that a,a-b,d-c are in G.P.
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a, b and c are in AP therefore:
b = a + c / 2
2b = a + c - (i)
a, b and d are in GP therefore:
b = √ad
b² = ad - (ii)
now multiply eq (i) with a
=> 2ab = a² + ac
=> -ac = a² - 2ab
=> b² - ac = a² - 2ab + b²
=> b² - 2ac = (a+b)²
=> ad - ac = (a+b)² (from eq (ii))
=> a (d-c) = (a+b)²
=> a, a-b, and d-c are in GP
Hence, Proved
Hope it helps...
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