if A,B,C are in A.P and B=π/4,then tanAtanBtanC=
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Terms in A.P have same common difference.
Let x, y, z are in A.P ,then 2y= x+z
Given,
A,B,C are in A.P
⇒ 2B = A+C (B =π/4 = 45 degree)
2(45) = A+C
A+C=90
A = (90-C)
tanA= tan(90-C)
that is tanA.tanC =1
Therefore :
tanAtanBtanC = 1.tan(45)
= 1
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