Question

If a b c are in A.P. Then line 2ax+3by+3c=0 always passes through fixed point

Answer 1

Step-by-step explanation:

Given If a b c are in A.P. Then line 2ax+3by+3c=0 always passes through fixed point

• If a,b,c are in A.P then 2b = a + c
•               Or 2b – a – c = 0
• Or we get a – 2b + c = 0
• So the straight line is given by 2ax + 3by + 3c = 0
• So the two equations are a – 2b + c = 0
•                                     So 2ax + 3by + 3c = 0
• Multiply the first equation by 3 we get
•                                 So 3a – 6b + 3c = 0
•                                      2ax + 3by + 3c = 0 (so constants are equal)
• Now to get the value of x and y we get
•                      2x = 3 or x = 3/2
•             Also 3y = - 6 or y = - 6 / 3
•                                    Or y = - 2
• Now we get the points as (3/2 , - 2)

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https://brainly.in/question/1678971