If a;b;c are in A.P then prove that 1/a;1/b;1/c are also in A.P
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its is not possibe
let 2 , 3 , 4 are in AP where d =1
but In
1/2 , 1/3 , 1/4 difference is not common
in 1/2 & 1/3 d=1/3-1/2 =>2-3/6 = -1/6
in 1/3 & 1/4 d = 1/4 - 1/3 => 3-4/12 = -1/12
as difference is not common these are not in AP
if this answer helps u then plz mark it as BRAINLIST ANSWER
let 2 , 3 , 4 are in AP where d =1
but In
1/2 , 1/3 , 1/4 difference is not common
in 1/2 & 1/3 d=1/3-1/2 =>2-3/6 = -1/6
in 1/3 & 1/4 d = 1/4 - 1/3 => 3-4/12 = -1/12
as difference is not common these are not in AP
if this answer helps u then plz mark it as BRAINLIST ANSWER
Sandeep03edu:
thnku
Answered by
0
if a,b,c are in A.P. then 1/a,1/b,1/c are in H.P. The question is wrong
sorry...im adding one more question check it out...
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