Question

If a;b;c are in A.P then prove that 1/a;1/b;1/c are also in A.P

Answer 1

its is not possibe

let 2 , 3 , 4 are in AP where d =1

but In
1/2 , 1/3 , 1/4 difference is not common

in 1/2 & 1/3 d=1/3-1/2 =>2-3/6 = -1/6

in 1/3 & 1/4 d = 1/4 - 1/3 => 3-4/12 = -1/12

as difference is not common these are not in AP

if this answer helps u then plz mark it as BRAINLIST ANSWER

Answer 2

if a,b,c are in A.P. then 1/a,1/b,1/c are in H.P. The question is wrong