If a b c are in
a.p. then prove that (a-c)^2=4(b^2-ac)
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Answered by
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A, b, c are in A. P.
SO,
We can say that,
=> b - a = c - b
or, c +a = 2b
Squaring both sides
=-=-=-=-=-=-=-=-=-=-=-=
=> ( c +a) ² = (2b)²
or, (c - a) ² +4ac = 4b²
or, (c-a) ² = 4b² - 4ac
or, (c-a) ² = 4(b² - ac)
____<proved>______
Hope this is ur required answer
Proud to help you
SO,
We can say that,
=> b - a = c - b
or, c +a = 2b
Squaring both sides
=-=-=-=-=-=-=-=-=-=-=-=
=> ( c +a) ² = (2b)²
or, (c - a) ² +4ac = 4b²
or, (c-a) ² = 4b² - 4ac
or, (c-a) ² = 4(b² - ac)
____<proved>______
Hope this is ur required answer
Proud to help you
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0
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