Question

If a, b, c are in A.P. then show that the terms |
given below are also in A.P:
(1) b+C, C+a, a + b

2.b+c-a, c+a-b, a+b-c
​

Answer 1

Answer:

both the sequence are in AP

Answer 2

Step-by-step explanation:

$let \: the \: common \: difference \: of \: this \: ap \: be \: d$

so, first term = A ....... ( i )

B = a+ d ........ ( i )

C = a + 2d ..... (iii)

adding eq i and ii

A + B = 2a + d

adding eq ii and iii

B + C = 2a + 2d

adding eq i and iii

C + A = 2a + 3d

• as here we see that in eq iv, v and vi , the common difference is D
• so, it is form an ap
• hence, A+B, B+ C, C+A ARE IN Ap

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