If a, b, c are in A.P. then show that the terms |
given below are also in A.P:
(1) b+C, C+a, a + b
2.b+c-a, c+a-b, a+b-c
Answers
Answered by
1
Answer:
both the sequence are in AP
Answered by
2
Step-by-step explanation:
so, first term = A ....... ( i )
B = a+ d ........ ( i )
C = a + 2d ..... (iii)
adding eq i and ii
A + B = 2a + d
adding eq ii and iii
B + C = 2a + 2d
adding eq i and iii
C + A = 2a + 3d
- as here we see that in eq iv, v and vi , the common difference is D
- so, it is form an ap
- hence, A+B, B+ C, C+A ARE IN Ap
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