If a,b,c are in AP b,c,d are in GP and 1/c,1/d,1/e are in Ap then prove that a,c,e are in AP
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Hey
knock knock .. an alteeeeerrrration.... The terms --> a , c , e ... form a GP and not an AP...
( Proof in the attached image ✓✓ )
However, if you still say that your Terms form an AP, then perhaps... a = c = e would be your case ...
Hope it helps ^_^>
knock knock .. an alteeeeerrrration.... The terms --> a , c , e ... form a GP and not an AP...
( Proof in the attached image ✓✓ )
However, if you still say that your Terms form an AP, then perhaps... a = c = e would be your case ...
Hope it helps ^_^>
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