If a b c are in AP prove a+k,b+k and c+k are in AP
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We know, 2 × middle term = sum of remaining two.
So,
➡ 2 × b = a + c
➡ 2b = a + c -------: ( 1 )
If b + c , c + a , a + b are also in A.P.
2 × ( c + a ) = b + a + b + c is true
Or, 2 × ( c + a ) = c + a + b + b is true
Or, 2 × ( c + a ) = c + a + 2b is true
Or, 2 × ( 2b ) = 2b + 2b is true
Or, 4b = 4b is true
0 = 0
Hence, both are equal. It means that b + c , c + a , a + b are in A.P.
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