if a, b, c are in AP then B minus A equal to
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first digit=a
common difference =d
b=a+d
then b-a=a+d-a=d
so, b-a = d
common difference =d
b=a+d
then b-a=a+d-a=d
so, b-a = d
kingofkings00016:
whose
Answered by
1
from properties of A.P.
=> 2b=a+c
=> b - a= c-b
therefore. if a, b, c are in AP then B minus A equal to c minus b
=> 2b=a+c
=> b - a= c-b
therefore. if a, b, c are in AP then B minus A equal to c minus b
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