if a,b,c are in ap then proove that 1/ab, 1/bc, 1/ca
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Answer:
If a,b,c are in AP,
b-a = c-b
to prove 1/bc, 1/ca, 1/ab are in AP, we need to show 1/ca - 1/bc = 1/ab - 1/ca
LHS:
1/ca - 1/bc = (b-a)/abc
RHS:
1/ab - 1/ca = (c-b)/abc
but we know that (b-a) = (c-b)
thus LHS = RHS.
Hence 1/bc, 1/ca, 1/ab are in AP.
Note: Calculation of 1/ca - 1/bc
You need to first take the LCM of ca and bc which is abc and do the calculation. I have calculated like this above.
Or
=1/ca-1/bc
=(bc-ca) /abc²
=c(b-a) / abc²
=b-a/abc
Here instead of taking LCM, i have multiplied the terms, which is fine. You will get the same answer.
Hence Proved
Step-by-step explanation:
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