If a b c are in ap then prove that (a-c)2=4(b2-ac)
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Answer:
b-a=c-b
b+b=a+c
2b=a+c
a=2b-c ......(1)
put in LHS of given proof
(2b-c-c)^2= (2b-2c)^2
=4(b-c)^2
=4(b^2+c^2-2bc)
=4{b^2 +c(c-2b)}
=4(b^2-ac) using (1)
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