Question

if a , b , c are in AP then prove that (a-c)2 = 4(b2 - ac).

if x, y, z are in GP and loga b . x log c b = 1 , then show that ax = by = cz .
plz any1 answer quickly.. its urgent....

Answer 1

Heya User,

--> a , b , c are in A.P. 

=> b - a = c - b
=> a + c = 2b

=> ( a + c )² = 4b²
=> a² + c² + 2ac = 4b²
=> a² - 2ac + c² = 4b² - 4ac
=> ( a - c )² = 4b² - 4ac
=> ( a - c )² = 4( b² - ac ) ^_^ And we're done..

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--> About the second part of the question.. Plz be a little clear ^_^

Answer 2

Answer:

Step-by-step explanation:

If a b and c are in AP then B minus A equals to C minus b Their employees b + b equals to a + c that implies to be equals to C + a day for a + C whole square equals to 40 square Their employees a square + c square + 2 AC = 24 p square then subtracting 4 AC from both sides Their employees a square minus 2 AC + c square equals to 4 B square minus 4 AC Their employees a minus C whole square equals to 4 into B square minus A C in the bracket hence proved