If a,b,c are in AP then show that a2(b+c)+b2(c+a)+c2(a+b) = 2/9(a+b+c)3
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Step-by-step explanation:
To Prove : (a+b+c)(a−b+c)=a2+b2+c2
Proof : a,b,c are in continued proportion.
∴ ba=cb=k (let)
b=ck
a=bk=(ck)k =ck2
L.H.S. =(ck2+ck+c)(ck2−ck+c)
=c2(k2+k+1)(k2−k+1)
=c2[(k2+1)2−(k)2]
=c2[k4+2k2+1−k2]
=c2[k4+k2+1]
R.H.S. =c2k4+c2k
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