Question

If a,b,c are in Arithmetic Progression then prove that b+c, c+a, a+b are in Arithmetic Progression

Answer 1

Step-by-step explanation:

a=a

b=a+d

c=a+2d

b+c=2a+3d=A

c+a=2a+2d=B

a+b=2a+d=C

for A.P,

B-A= C-B

B-A= 2a+2d-2a-3d=-d

C-B=2a+d-2a-2d= -d

so, it is in arithmetic progression