if a, b, c are in continued proportion prove(a+b+c) (a-b+c) =a^2+b^2+c^2
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Answer:
LHS
(a+b+c) (a-b+c) = a^2 -b^2 + c^2 -ab +ab + bc - bc +ac+ac
= a^2-b^2+c^2 + ac+ac
= a^2-b^2+c^2 + b^2+b^2 (as b^2 = ac )
=a^2+b^2+c^2
RHS
a^2+b^2+c^2
proved
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