Math, asked by shiwangi8045, 6 months ago

if a,b,c are in continued proportion,prove that (a^2-b^2)(b^2+c^2)=(b^2-c^2)(a^2+b^2)​

Answers

Answered by vanshusaini703
1

Answer:

a^2 b^2+a^2 c^2-b^4-b^2 c^2=a^2 b^2+b^4-a^2 c^2-b^2 c^2

a^2 b^2-b^2 c^2=a^2 b^2-b^2 c^2

L.H.S = R.H.S

HENCE PROVED

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