If a, b, c are in continued proportion, prove that
a/c = 2a^2-5ab+7b^2/2b^2-5ab+7c^2
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Step-by-step explanation:
given
a/b =b/c =K
then
a=bk and b=ck
a = (ck)k = ck^2 and b= can
LHS = a/c=ck/c
=k^2
RHS =2a^2 -5ab+7b^2/2b^2-5bc+7c^2 = 2(ck^2)^2 -5(ck^2)ck+7(ck)^2/2(ck)^2-5(ck)c+7c^2
After solving this equation the answer will be k^2
LHS = RHS
HENCE PROVED
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