if a,b,c are in continued proportion prove that a²+ab+b²/b²+bc+c²=a/c
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Step-by-step explanation:
a , b,c Are in continued proportion
=> a:b::b:c
=> b²=ac
lhs:
a²+ab+b²/ b²+bc+c²
replace b²=ac
a²+ab+ac/ac+bc+c²
=a(a+b+c)/c(a+b+c)
= a/c (rhs)
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