If a,b,c are in continued proportion prove that a²+ab+b²:b²+bc+c²=a:c
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Step-by-step explanation:
Here
b
a
=
c
b
∴b
2
=ac
i)LHS=
b
2
+bc+c
2
a
2
+ab+b
2
=
ac+bc+c
2
a
2
+ab+ac
[Putting b
2
=ac]
=
c(a+b+c)
a(a+b+c)
=
c
a
=RHS
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