If a,b,c are in continued proportion then show that (a+b)2/ ab = (b+c)2/ bc
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Answer:
a:b = b:c
a/b = b/c
adding 1 both sides,
(a+b) /b = (b+c) /c
multiply 2,
2(a+b) /b = 2(b+c) /c
cross Multiplication,
2(a+b)c = 2(b+c)a
divide abc on both sides,
2(a+b) /ab = 2(b+c) /bc
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