If a,b,c are in G.P and a^(1/x)=b^(1/y)=c^(1/z),Prove that x,y,z are in A.P
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:z , c = ky, b = kxa = k k (let) =z = c1/y = b1/x1/a
now a,b,c are in g.p. (given)
hence b/a = c/b
ky / kx = kz / ky
k(2y) = k(x +z)
hence 2y = x + z
hence x, y, z will be in A.P
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