if a,b,c are in g.p and x and y are the Am between a,b and b,c respectively show that a÷x+c÷y=2
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b^2 = a × c
b/a = c/b = k...(let)
x = (a+b)/2
a/x = 2 /(k+1)
y = (c+b)/2
c/y = 2k/(k+1)
Therefore, a/x + c/y = 2/(k+1) + 2k/(k+1) = 2
b/a = c/b = k...(let)
x = (a+b)/2
a/x = 2 /(k+1)
y = (c+b)/2
c/y = 2k/(k+1)
Therefore, a/x + c/y = 2/(k+1) + 2k/(k+1) = 2
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