Math, asked by bharti4455, 1 year ago

If a,b,c are in gp, a+h,b+h,c+h are in hp,then the value of h is?

Answers

Answered by Amritha16112005
0

= ( 1/a + 1/b - 1/c )( 1/b + 1/c - 1/a )

= [ 1/b + ( 1/a - 1/c ) ] · [ 1/b - ( 1/a - 1/c ) ]

= (1/b)² - ( 1/a - 1/c )²

= 1/b² - [ ( 1/a² + 1/c² ) - 2/ac ]

= 1/b² - { [ ( 1/a + 1/c )² - 2/ac ] - 2/ac } ..... Note This Step

= 1/b² - [ ( 1/a + 1/c )² - 4/ac ]

= 1/b² - [ ( 2/b )² - 4/ac ] ................ from (1)

= 1/b² - 4/b² + 4/ac

= 4/ac - 3/b²

Similar questions