Question

If a,b,c are in GP prove that a^2b^2c^2 [1/a^3 + 1/b^3 +1/c^3] = a^3 + b^3 + c^3

Answer 1

a(b2+c2)=c(a2+b2) , 2) A2b2c2(1a3+1b3+1c3)=a3+b3+c3 , 3) (a+b+c)2a2+b2+c2=a+b+ca-b+c , 4)1a2-b2+1b2=1b2-c2 ,5) (a+2b=2c)(a-2b+2c)=a2+4c2

follow me