if a b c are in GP prove that a into A ( B square + C square) = C (A square + B square)
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let a = x/r .b= x & c= xr.
then, a(b*b+c*c)=x/r(x square +(xr)square)
=x*r/r square (x square +(xr)square)
=xr((x/r)square + x square)
= c( a square +b square)
proved
then, a(b*b+c*c)=x/r(x square +(xr)square)
=x*r/r square (x square +(xr)square)
=xr((x/r)square + x square)
= c( a square +b square)
proved
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