Question

If a, b, c are in GP prove that a³,b³,c³ are in gp

Answer 1

Answer:

Step-by-step explanation:

∵a,b,c are in g.p

∴b/a=c/b     (the common ratios of numbers in g.p are equal)

⇒(b/a)³=(c/b)³  (cubing both sides )

⇒b³/a³=c³/b³

∴Numbers a³,b³,c³ are in g.p

Answer 2

Answer:

answer` is prooved

Step-by-step explanation:

Given, a,b,c are in g.p

We know that b/a=c/b =r (r is common ratio)

                 C.O.B.S

⇒(b/a)³=(c/b)³  (cubing both sides )

⇒b³/a³=c³/b³

∴Numbers a³,b³,c³ are in g.p  Hence Prooved