If a,b, c are in GP show that 1/a,1/b,1/c are also in GP
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Step-by-step explanation:is in the attachment I have provided
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Given:
The terms in GP = a, b and c
To Find:
1/a,1/b,1/c are also in GP
Solution:
As per the question, it is given that three terms a,b,c are in G.P.
Therefore,
b² = ac
Now,
We also need to show that, other three terms 1/a,1/b,1/c are also in G.P.
Hence,
(1/b)² = ( 1/a) × (1/c)
(1/b)² = ( 1/ac)
After cross multuplying -
b² = ac
Hence it is proved that, 1/a,1/b,1/c are in G.P.
Answer: The terms 1/a,1/b,1/c are in G.P.
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