Question

If a,b,c are in h.p. and a>c>0, then 1/(b-c)+1/(a-b)
(1) is positive
(2) is zero
(3) is negative
(4)has no fixed sign

Answer 1

Answer:

If a,b,c are in h.p. and a>c>0, then 1/(b-c)+1/(a-b)

(1) is positive

Answer 2

Answer:  positive

Step-by-step explanation:       a,b,c is in H.P

therefore , b= 2ac/a+c

substitute b with 2ac/a+c  in 1/B-C - A/A-B

AFTER EVALUATIONG ....    a+c/ac-c^2 - a+c/a^2-ac

denominator has (a-c) as comon factor ,

after adding fractions,  we get ..   a+c/ac = 1/c  + 1/a

as a and c are positive ,   1/c + 1/a is positive