Question

If a , b, c are inG.P and a to the power 1 /x = b to the power 1/ y = c to the power 1/z , prove that x,y,z are in gp​

Answer 1

$\huge\mathfrak{Solution}$

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Answer 2

Step-by-step explanation:

Let a^1/x=b^1/

y=c^1/z=m .

soa=m^x,b=m^y,

c=m^z.

Now a b c are in gp

o b^2=ac.

This imply m^2y=m^z.

m^x so comparing we get 2y=x+z.

Hence a b c are in ap