If A, B, C are interior angle of a triangle abc then show tan (A+B/2) =cot c/2
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Step-by-step explanation:
In A triangle ,
A + B + C = 180°[Angle Sum Property Of Triangle]
Divide both sides by 2
A + B + C/2 = 180/2
A + B/2 + C /2 = 90
A + B/2 = 90 - C/2
Taking Tan On both sides ,
Tan (A + B/2) = Tan(90 - C/2)
Tan (A +B/2) = Cot (C/2)
Hence Proved.....
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