If a b c are interior angle of triangle then show that tan (c+a)/2 = cot (b/2 )
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Answer:
Step-by-step explanation:
If a b c are interior angle of triangle
then a+b+c=180
c+a=180-b
(c+a)/2=(180-b)/2=90-b/2
(c+a)/2=90-b/2
tan(c+a)/2=tan(90-b/2)=cotb/2
tan(c+a)/2=cot b/2
proved
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