if a b c are interior angles of triangle ABC show that tan square b + c by 2 is equal to cosec squared A 2 minus 1
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firstly just prove B+C/2=90-A/2
THEN USE IDENTITY, (IN LHS)
TANSQ.(90-A/2)=COTSQ.(A/2)
THEN, (IN RHS)
COSECSQ.(A/2) - 1 = COTSQ.(A/2)
THEREFORE L.H.S=R.H.S
THEN USE IDENTITY, (IN LHS)
TANSQ.(90-A/2)=COTSQ.(A/2)
THEN, (IN RHS)
COSECSQ.(A/2) - 1 = COTSQ.(A/2)
THEREFORE L.H.S=R.H.S
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