if a b c are interior angles of triangle ABC show that tan a + b upon 2 is equal to cot c / 2
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In triangle sum of interior angles=180⁰ Α+B+ C=180⁰ Α+B. =180⁰-C ... Taking tangent tan( A+B)/2=tan(90⁰-C/2) tan(A+B)/2=Cot(C/2)
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