Question

if a b c are interior angles of triangle abc the show that sec(a+b)/2 = cosec(c/2)​

Answer 1

Step-by-step explanation:

a b c are interior angles of triangle abc implies

a+b+c = 180.

implies a+b = 180- c

implies [a+b]/2 = [180- c]/2 --------(1)

sec(a+b)/2 = sec[180- c]/2

= cosec[90 - c/2]

= cosec [c/3]

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