Question

. If A,B,C are mutually exclusive and exhaustive events of an experiment s.t. 3 P(A) = 2 P(B) = P(C) . Find P(A) ?
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Answer 1

Answer

Given A,B,C are three mutually exclusive ξ exhaustive events.

⇒P(A)=2P(B)=3P(C)

⇒P(A∪B∪C)=P(A)+P(B)+P(C)

                                  =2P(B)+P(B)+311P(B)

                                  =36P(B)+3P(B)+2P(B)=311P(B)

⇒P(A∪B∪C)=P(A)+P(B)+P(C)=1

⇒1=311P(B)

⇒P(B)=113=226

Hence, the answer is 226.