if a, b ,c are mutually perpendicular then show that c× (a×b)= 0 is the converse true?
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If A, B, and C are mutually perpendicular, how can you show that c×(A×B)=0? ... This means that θ = 0 or π, and since sin0 = sinπ = 0, thus C x (A x B) = 0. The converse isn't true, as as long as C is perpendicular to both A and B, it can be true.
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