Question

If a,b,c are natural numbers, then how many solutions are there for a+b+c= 21​

Answer 1

Answer:

if a+b+c=21

then, a=21-b-c

b=21-a-c

c=21-a-b

a+b=21-C

b+c=21-a

a+c=21-b

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Hope this will help you. . . . .

Answer 2

Answer:

Concept - Permutations

Given a + b+ c = 21 and a,b,c is natural numbers.

Problem : find the number os solution

Step-by-step explanation:

Since we know that a ,b and c is a natural number

a + b + b =21

Let a=x+1,b=y+1,c=z+1 where x,y,z;ϵW

x + y + z =18

Therefore the permutation is  20! / 18! *2!  = 20*19/2 = 190

Hence answer is 190 solution is possible.

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