Question

If a,b,c, are natural numbers where a>b
Then write Pythagorean triplet

Answer 1

The Pythagorean triplet is $c^{2} =a^{2} +b^{2}$.

Step-by-step explanation:

We have,

a, b and c = natural numbers

a > b

To find, Pythagorean triplet = ?

We know that,

The Pythagorean triplet,

$h^{2} =p^{2} +b^{2}$

Where, h = hypotaneous, b = base and p = perpendicular

Here, h > (a, b)

The Pythagorean triplet,

$c^{2} =a^{2} +b^{2}$

Answer 2

Answer:

this is correct answer

Step-by-step explanation:

If a, b, c are natural number where a>b, then ( a square+ b square ),( a square- b square ), (2ab ) is a phythagorean triplet.