Question

if a b c are non zero of and a + b + c = 0 then a square upon BC + b square upon CA + c square Upon A B equals to​

Answer 1

Step-by-step explanation:

Given , a+b+c=0

To prove, a*2/bc +b*2/ca+c*2ab =0

Proof,

=a(a*2/bc) + b(+b*2/ca) +c(c*2ab)

=a*3+b*3 + c*3÷abc

=(From equation)a*3 +b*3+c*3=3abc

=ie , from this ,a*3+b*3 + c*3÷abc

We get, 3abc÷abc

=3

Hence proved mark me as brainlist