Question

if a,b,c are non zero real numbers , then determinant= c1(1,1,1) c1(ab,bc,ca) c3(1/a+1/b,1/b+1/c,1/c+1/b) is?

Answer 1

the answer is 0 means option (a), first step is R1 tends to R1-R3, R2 tends to R2-R3, then the remaining elements is C1 (0,0,1),C2(ab-ca,bc-ca,ca),C3(1/a+1/b-1/c-1/a,1/b+1/c-1/c-1/a,1/c+1/a), in C3 the remaining elements be(1/b-1/c),(1/b-1/a,1/c+1/a) in next line expand along C1, 1[a(b-c) thodi si jagah chorkar c-b/bc in next line of big bracket c(b-a) a-b/ab], in next line we take common (b-c)(b-a) in the sign of determinant the remaining elements be [(a -1/bc in next line c -1/ab] next line (b-c)(b-a) Culley bracket a into -a/b-(c into -1/bc), (b-c)(b-a)(-1+1)=0 Ans hope it's help you please mark it as a brainiest answer