If A,B,C are non zero square matrices of same order,then which one of the foolowing is not true
a)AB=BA
b)A(B+C)=AB+AC
Answers
Answer:
Answer
Let us assume that A is non-singular i.e. |A|
= 0 and hence A
−1
exists such that AA
−1
=I.
∴ AB=0
⟹ A
−1
(AB)=(A
−1
A)B=IB=B=0
Above shows that B is a null matrix which is a contradiction.
Similarly, if B is non-singular then as above we will have A=0 which is again a contradiction. hence, both A and B must be singular.
Step-by-step explanation:
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SOLUTION
TO DETERMINE
If A , B , C are non zero square matrices of same order , then which one of the following is not true
a) AB = BA
b) A(B+C) = AB + AC
CONCEPT TO BE IMPLEMENTED
Matrix :
We know that a system of mn numbers arranged in a rectangular formation along M rows and n columns and bounded by the brackets is called m by n matrix which is written as m × n matrix.
A Matrix having n rows and n columns is called a square matrix of order n
EVALUATION
a) Matrix multiplication is not commutative
So AB = BA does not hold
For example let us assume that
Then
Thus AB ≠ BA
b) Matrix follows the distributive property
FINAL ANSWER
The untrue property on matrix is AB = BA
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