Question

if A,B,C are positive acute angles and sin(B+C-A)=cos(C+A-B)=tan(A+B-C)=1 then A,B,C are

Answer 1

As sin (B+C-A)=1; cos (C+A-B)=1 and tan (A+B-C)=1; that implies B+C-A=90 degrees
eqn 1 C+A-B=0 degrees eqn 2 A+B-C=45 degrees .eqn 3 Solving the three equations we get A=22.5 degrees; B=67.5 degrees and C=45 degrees.