Math, asked by insane32, 4 months ago

If a, b, c are positive real numbers such that \frac{a+b-c}{c}=\frac{a-b+c}{b}=\frac{a+b+c}{a} then find the value of \frac{(a+b)(b+c)(c+a)}{abc}=1 ?​

Answers

Answered by shinythomas985
1

Answer:

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