Question

If a,b,c are positive real such that a (b+c) =32, b(c+a) = 65 and c(a+b) - 77 the abc.
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Answer 1

Answer:

ab+ac=32 ->ab=32-ac

ac+cb=77 ->cb=77-ac

ab+cb=65 ->(32-ac)+(77-ac)=65

-2ac=65-109

2ac=44

ac=22

cb=55

ab=10

a².b².c²=22.55.10

(a.b.c)²=12100

a.b.c=110