Question

if a,b,c are real no then ∆=
|a-1,a,a+1,b-1,b,,b+1,c-1,c,c+1|​

Answer 1

Answer:

type the question correctly please.

I can't understand what is it

Answer 2

Here's what you need -

Answer

[(1+a)(1+b)(1+c)]

7

>7

7

a

4

b

4

c

4

i.e.,(1+∑a+∑ab+abc)>7(abc)

4/7

Since, AM>GM

a+b+c+≥3(abc)

1/3

ab+bc+ac≥3(a

2

b

2

c

2

)

1/3

Hence,

1+∑a+∑ab+abc≥1+3(abc)

1/3

+3(abc)

2/3

+abc1+∑a+∑ab+abc≥1+(abc)

1/3

+(abc)

1/3

+(abc)

1/3

+(abc)

2/3

+(abc)

2/3

+(abc)

2/3

+abc

So,

LHS≥7[1(abc)

1/3

(abc)

1/3

(abc)

1/3

(abc)

2/3

(abc)

2/3

(abc)

2/3

(abc)]

1/7

≥7[(abc)

9/3

(abc)]

1/7

≥7(abc)

4/7