If a,b,c are real numbers and a^2+b^2+c^2-ab-bc-ca=0,then show that a=b=c
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Answer:
Step-by-step explanation:
Proof by reverse assumption method
let us assume that a = b = c,
that is a = b
a = c
so when we take the expression a²+b²+c²-ab-bc-ac,
the same will be written as,
a² + a² + a² - a*a - a*a - a*a
=> 3a² - a² - a² -a²
=> 3a² - 3a²
= 0
so, a²+b²+c²-ab-bc-ac = 0 if a = b = c
and therefore
if a²+b²+c²-ab-bc-ac=0 then a = b = c
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