. If a,b,c are real numbers such that ac≠0 then show that at least one of the equations ax² + bx + c = 0 and -ax² + bx + c = 0 has real roots.
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1
Answer:
Given,
f(x)=ax
2
+bx+c
g(x)=bx
2
+cx+a
If we set t as the common root, then we know that f(t)=g(t)=0:
at
2
+bt+c=bt
2
+ct+a
We can equate coefficents to conclude that a=b=c
Therefore, we can say that
abc
a
3
+b
3
+c
3
=
aaa
a
3
+a
3
+a
3
=
a
3
3a
3
=3
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