if a b c are sides of a triangle and 's'be it's semiperimetre and (S-a) 90 (S-b) 50 (S-c) =10. then find the value of a.
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a,b,c are sides of a triangle.
Formula for Semi perimeter,
S= a+b+c/2
→ a + b + c = 2 S ----(A)
Also, s-a = 90,-----(1)
s-b =50,--------(2)
s-c= 10-------(3)
Adding (1) ,(2) and (3), we get
→3 s -a-b-c =90+50 +10
→ 3 s -(a+b+c) = 150
→3 S - 2 S = 150 [ Using A]
→ S = 150
As,→ S-a= 90
→150 -a =90
→ a = 150 - 90
→ a =60
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