If a,b,c are sides of a triangle and s be its semi –perimeter and (s-a) =90, (s-b)=50 , (s-c)=10 ,then find value a.
Answers
Answered by
0
Answer:s=a+b+c/2
Explanation:let s is equal to x (x-a)=50. A=50-x
Answered by
1
Answer:
= a+b+c/ 2
=90+50+10/2
=150/2
=75
a=75
Similar questions