Question

If a, b, c are sides of a triangle and 's' be its semiperimeter and (s-a) =90, (s-b) =50,(s-c)=10. Then find the value of 'a'.

Answer 1

here is your answer

hope its help you

Answer 2

Answer- A triangle is a figure with 3 sides.

Sides of triangle= a, b, c

Perimeter of triangle= Sum of all sides = a+b+c

Semiperimeter of triangle(s)= Sum of all sides/2 = (a+b+c)/2

(s-a)= 90 -(1)

(s-b)= 50 -(2)

(s-c)= 10 -(3)

Adding all 3 equations,

(s-a)+(s-b)+(s-c)= 90+50+10

s-a+s-b+s-c= 150

3s-(a+b+c)= 150

3s- 2s= 150

[ ∵a+b+c= perimeter

but perimeter= 2s]

s=150

Substituting value of s in equation (1),

s-a= 90

150-a= 90

150-90= a

So, value of a= 60